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意法半导体软件笔试真题

更新时间:2023-08-18 19:19:12 高考知识网 www.xjdkctz.com

  a test for the c programming language

  i. history

  1. c was originally designed for and implemented on the (what) operating system on the dec pdp-11, by (who) .

  2. the most recently approved ansi/iso c standard was issued in (when) , and single line comments notation “//” is or isn’t a feature of c89.

  ii. syntax and semantics

  1. in a runtime c program, auto variables are stored in , static variables are stored in , and function parameters are stored in .

  a. stack b. heap c. neither stack nor heap

  2. the statement “extern int x;” is a , and the keyword extern is used during .

  a. variable declaration b. variable definition

  c. compilation time d. runtime

  3. there is a complicated declaration: void ( * signal (int, void (*)(int)) ) (int);

  if a statement “typedef void (*p) (int);” is given, please rewrite this complicated declaration.

  4. the following code is a segment of c program.

  ..........

  void func(int *p)

  {...........}

  ..........

  main()

  {

  int num=0;

  .........

  func(&num);

  ........

  }

  ..........

  here, the function argument “&num” is passed .

  a. by value b. by reference

  iii. practice

  create a tree, which has h (h>0) layers, and its each node has w (w>0) sub-nodes.

  please complete the following incomplete solution.

  #include

  #include

  struct tree{

  char info;

  p_sub; //link to sub-nodes

  };

  // allocate memory and initiate

  void dnode ( struct tree* tmp )

  {

  =malloc( sizeof (struct tree) );

  = 0x41;

  = null;

  }

  struct tree *dtree (struct tree* subtree, int height, int width)

  {

  int i;

  if ( !subtree ) //if necessary, allocte memory for subtree

  denode(subtree);

  if ( height == 1 )

  return subtree;

  else if ( height == 2 ) {

  struct tree *leaf = null;

  for ( i=0; i

  denode ( );

  ;

  leaf = null;

  }

  return subtree;

  }

  else {

  for ( i=0; i

  }

  return subtree;

  }

  }

  main()

  {

  .........

  struct tree *root = null;

  root = dtree (root, h, w) ; // h and w are integers get from input

  .........

  }